Metamath Proof Explorer


Theorem sseqtrid

Description: Subclass transitivity deduction. (Contributed by Jonathan Ben-Naim, 3-Jun-2011)

Ref Expression
Hypotheses sseqtrid.1 ⊢ B ⊆ A
sseqtrid.2 ⊢ φ → A = C
Assertion sseqtrid ⊢ φ → B ⊆ C

Proof

Step Hyp Ref Expression
1 sseqtrid.1 ⊢ B ⊆ A
2 sseqtrid.2 ⊢ φ → A = C
3 1 a1i ⊢ φ → B ⊆ A
4 3 2 sseqtrd ⊢ φ → B ⊆ C