Metamath Proof Explorer


Theorem sseqtrid

Description: Subclass transitivity deduction. (Contributed by Jonathan Ben-Naim, 3-Jun-2011)

Ref Expression
Hypotheses sseqtrid.1 ⊢ 𝐵 ⊆ 𝐴
sseqtrid.2 ⊢ ( 𝜑 → 𝐴 = 𝐶 )
Assertion sseqtrid ( 𝜑 → 𝐵 ⊆ 𝐶 )

Proof

Step Hyp Ref Expression
1 sseqtrid.1 ⊢ 𝐵 ⊆ 𝐴
2 sseqtrid.2 ⊢ ( 𝜑 → 𝐴 = 𝐶 )
3 1 a1i ⊢ ( 𝜑 → 𝐵 ⊆ 𝐴 )
4 3 2 sseqtrd ⊢ ( 𝜑 → 𝐵 ⊆ 𝐶 )