Metamath Proof Explorer


Theorem elpm

Description: The predicate "is a partial function". (Contributed by NM, 15-Nov-2007) (Revised by Mario Carneiro, 14-Nov-2013)

Ref Expression
Hypotheses elmap.1 ⊢ A ∈ V
elmap.2 ⊢ B ∈ V
Assertion elpm ⊢ F ∈ A ↑ 𝑝𝑚 B ↔ Fun ⁡ F ∧ F ⊆ B × A

Proof

Step Hyp Ref Expression
1 elmap.1 ⊢ A ∈ V
2 elmap.2 ⊢ B ∈ V
3 elpmg ⊢ A ∈ V ∧ B ∈ V → F ∈ A ↑ 𝑝𝑚 B ↔ Fun ⁡ F ∧ F ⊆ B × A
4 1 2 3 mp2an ⊢ F ∈ A ↑ 𝑝𝑚 B ↔ Fun ⁡ F ∧ F ⊆ B × A