Metamath Proof Explorer


Theorem epfrc

Description: A subset of a well-founded class has a minimal element. (Contributed by NM, 17-Feb-2004) (Revised by David Abernethy, 22-Feb-2011)

Ref Expression
Hypothesis epfrc.1 ⊢ B ∈ V
Assertion epfrc ⊢ E Fr A ∧ B ⊆ A ∧ B ≠ ∅ → ∃ x ∈ B B ∩ x = ∅

Proof

Step Hyp Ref Expression
1 epfrc.1 ⊢ B ∈ V
2 1 frc ⊢ E Fr A ∧ B ⊆ A ∧ B ≠ ∅ → ∃ x ∈ B y ∈ B | y E x = ∅
3 dfin5 ⊢ B ∩ x = y ∈ B | y ∈ x
4 epel ⊢ y E x ↔ y ∈ x
5 4 rabbii ⊢ y ∈ B | y E x = y ∈ B | y ∈ x
6 3 5 eqtr4i ⊢ B ∩ x = y ∈ B | y E x
7 6 eqeq1i ⊢ B ∩ x = ∅ ↔ y ∈ B | y E x = ∅
8 7 rexbii ⊢ ∃ x ∈ B B ∩ x = ∅ ↔ ∃ x ∈ B y ∈ B | y E x = ∅
9 2 8 sylibr ⊢ E Fr A ∧ B ⊆ A ∧ B ≠ ∅ → ∃ x ∈ B B ∩ x = ∅