Metamath Proof Explorer


Theorem eq0rdv

Description: Deduction for equality to the empty set. (Contributed by NM, 11-Jul-2014) Avoid ax-8 , df-clel . (Revised by GG, 6-Sep-2024)

Ref Expression
Hypothesis eq0rdv.1 ⊢ φ → ¬ x ∈ A
Assertion eq0rdv ⊢ φ → A = ∅

Proof

Step Hyp Ref Expression
1 eq0rdv.1 ⊢ φ → ¬ x ∈ A
2 1 alrimiv ⊢ φ → ∀ x ¬ x ∈ A
3 eq0 ⊢ A = ∅ ↔ ∀ x ¬ x ∈ A
4 2 3 sylibr ⊢ φ → A = ∅