Metamath Proof Explorer


Theorem eqleltd

Description: Equality in terms of 'less than or equal to', 'less than'. (Contributed by NM, 7-Apr-2001)

Ref Expression
Hypotheses ltd.1 ⊢ φ → A ∈ ℝ
ltd.2 ⊢ φ → B ∈ ℝ
Assertion eqleltd ⊢ φ → A = B ↔ A ≤ B ∧ ¬ A < B

Proof

Step Hyp Ref Expression
1 ltd.1 ⊢ φ → A ∈ ℝ
2 ltd.2 ⊢ φ → B ∈ ℝ
3 eqlelt ⊢ A ∈ ℝ ∧ B ∈ ℝ → A = B ↔ A ≤ B ∧ ¬ A < B
4 1 2 3 syl2anc ⊢ φ → A = B ↔ A ≤ B ∧ ¬ A < B