Metamath Proof Explorer


Theorem eqrdv

Description: Deduce equality of classes from equivalence of membership. (Contributed by NM, 17-Mar-1996)

Ref Expression
Hypothesis eqrdv.1 ⊢ φ → x ∈ A ↔ x ∈ B
Assertion eqrdv ⊢ φ → A = B

Proof

Step Hyp Ref Expression
1 eqrdv.1 ⊢ φ → x ∈ A ↔ x ∈ B
2 1 alrimiv ⊢ φ → ∀ x x ∈ A ↔ x ∈ B
3 dfcleq ⊢ A = B ↔ ∀ x x ∈ A ↔ x ∈ B
4 2 3 sylibr ⊢ φ → A = B