Metamath Proof Explorer


Theorem eqvreldisj1

Description: The elements of the quotient set of an equivalence relation are disjoint (cf. eqvreldisj2 , eqvreldisj3 ). (Contributed by Mario Carneiro, 10-Dec-2016) (Revised by Peter Mazsa, 3-Dec-2024)

Ref Expression
Assertion eqvreldisj1 ⊢ EqvRel R → ∀ x ∈ A / R ∀ y ∈ A / R x = y ∨ x ∩ y = ∅

Proof

Step Hyp Ref Expression
1 simpl ⊢ EqvRel R ∧ x ∈ A / R ∧ y ∈ A / R → EqvRel R
2 simprl ⊢ EqvRel R ∧ x ∈ A / R ∧ y ∈ A / R → x ∈ A / R
3 simprr ⊢ EqvRel R ∧ x ∈ A / R ∧ y ∈ A / R → y ∈ A / R
4 1 2 3 qsdisjALTV ⊢ EqvRel R ∧ x ∈ A / R ∧ y ∈ A / R → x = y ∨ x ∩ y = ∅
5 4 ralrimivva ⊢ EqvRel R → ∀ x ∈ A / R ∀ y ∈ A / R x = y ∨ x ∩ y = ∅