Metamath Proof Explorer


Theorem erALTVeq1d

Description: Equality theorem for equivalence relation on domain quotient, deduction version. (Contributed by Peter Mazsa, 25-Sep-2021)

Ref Expression
Hypothesis erALTVeq1d.1 ⊢ φ → R = S
Assertion erALTVeq1d ⊢ φ → R ErALTV A ↔ S ErALTV A

Proof

Step Hyp Ref Expression
1 erALTVeq1d.1 ⊢ φ → R = S
2 erALTVeq1 ⊢ R = S → R ErALTV A ↔ S ErALTV A
3 1 2 syl ⊢ φ → R ErALTV A ↔ S ErALTV A