Metamath Proof Explorer


Theorem erALTVeq1

Description: Equality theorem for equivalence relation on domain quotient. (Contributed by Peter Mazsa, 25-Sep-2021)

Ref Expression
Assertion erALTVeq1 ⊢ R = S → R ErALTV A ↔ S ErALTV A

Proof

Step Hyp Ref Expression
1 eqvreleq ⊢ R = S → EqvRel R ↔ EqvRel S
2 dmqseqeq1 ⊢ R = S → dom ⁡ R / R = A ↔ dom ⁡ S / S = A
3 1 2 anbi12d ⊢ R = S → EqvRel R ∧ dom ⁡ R / R = A ↔ EqvRel S ∧ dom ⁡ S / S = A
4 dferALTV2 ⊢ R ErALTV A ↔ EqvRel R ∧ dom ⁡ R / R = A
5 dferALTV2 ⊢ S ErALTV A ↔ EqvRel S ∧ dom ⁡ S / S = A
6 3 4 5 3bitr4g ⊢ R = S → R ErALTV A ↔ S ErALTV A