Metamath Proof Explorer


Theorem f1sn2g

Description: A function that maps a singleton to a class is injective. (Contributed by Zhi Wang, 1-Oct-2024)

Ref Expression
Assertion f1sn2g ⊢ A ∈ V ∧ F : A ⟶ B → F : A ⟶ 1-1 B

Proof

Step Hyp Ref Expression
1 fsn2g ⊢ A ∈ V → F : A ⟶ B ↔ F ⁡ A ∈ B ∧ F = A F ⁡ A
2 1 biimpa ⊢ A ∈ V ∧ F : A ⟶ B → F ⁡ A ∈ B ∧ F = A F ⁡ A
3 2 simpld ⊢ A ∈ V ∧ F : A ⟶ B → F ⁡ A ∈ B
4 f1sng ⊢ A ∈ V ∧ F ⁡ A ∈ B → A F ⁡ A : A ⟶ 1-1 B
5 3 4 syldan ⊢ A ∈ V ∧ F : A ⟶ B → A F ⁡ A : A ⟶ 1-1 B
6 f1eq1 ⊢ F = A F ⁡ A → F : A ⟶ 1-1 B ↔ A F ⁡ A : A ⟶ 1-1 B
7 2 6 simpl2im ⊢ A ∈ V ∧ F : A ⟶ B → F : A ⟶ 1-1 B ↔ A F ⁡ A : A ⟶ 1-1 B
8 5 7 mpbird ⊢ A ∈ V ∧ F : A ⟶ B → F : A ⟶ 1-1 B