Metamath Proof Explorer


Theorem fconst6g

Description: Constant function with loose range. (Contributed by Stefan O'Rear, 1-Feb-2015)

Ref Expression
Assertion fconst6g ⊢ B ∈ C → A × B : A ⟶ C

Proof

Step Hyp Ref Expression
1 fconstg ⊢ B ∈ C → A × B : A ⟶ B
2 snssi ⊢ B ∈ C → B ⊆ C
3 1 2 fssd ⊢ B ∈ C → A × B : A ⟶ C