Metamath Proof Explorer


Theorem fex2

Description: A function with bounded domain and codomain is a set. This version of fex is proven without the Axiom of Replacement ax-rep , but depends on ax-un , which is not required for the proof of fex . (Contributed by Mario Carneiro, 24-Jun-2015)

Ref Expression
Assertion fex2 ⊢ F : A ⟶ B ∧ A ∈ V ∧ B ∈ W → F ∈ V

Proof

Step Hyp Ref Expression
1 xpexg ⊢ A ∈ V ∧ B ∈ W → A × B ∈ V
2 1 3adant1 ⊢ F : A ⟶ B ∧ A ∈ V ∧ B ∈ W → A × B ∈ V
3 fssxp ⊢ F : A ⟶ B → F ⊆ A × B
4 3 3ad2ant1 ⊢ F : A ⟶ B ∧ A ∈ V ∧ B ∈ W → F ⊆ A × B
5 2 4 ssexd ⊢ F : A ⟶ B ∧ A ∈ V ∧ B ∈ W → F ∈ V