Metamath Proof Explorer


Theorem ffdmd

Description: The domain of a function. (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Hypothesis ffdmd.1 ⊢ φ → F : A ⟶ B
Assertion ffdmd ⊢ φ → F : dom ⁡ F ⟶ B

Proof

Step Hyp Ref Expression
1 ffdmd.1 ⊢ φ → F : A ⟶ B
2 ffdm ⊢ F : A ⟶ B → F : dom ⁡ F ⟶ B ∧ dom ⁡ F ⊆ A
3 1 2 syl ⊢ φ → F : dom ⁡ F ⟶ B ∧ dom ⁡ F ⊆ A
4 3 simpld ⊢ φ → F : dom ⁡ F ⟶ B