Metamath Proof Explorer


Theorem fieq0

Description: A set is empty iff the class of all the finite intersections of that set is empty. (Contributed by FL, 27-Apr-2008) (Revised by Mario Carneiro, 24-Nov-2013)

Ref Expression
Assertion fieq0 ⊢ A ∈ V → A = ∅ ↔ fi ⁡ A = ∅

Proof

Step Hyp Ref Expression
1 fveq2 ⊢ A = ∅ → fi ⁡ A = fi ⁡ ∅
2 fi0 ⊢ fi ⁡ ∅ = ∅
3 1 2 eqtrdi ⊢ A = ∅ → fi ⁡ A = ∅
4 ssfii ⊢ A ∈ V → A ⊆ fi ⁡ A
5 sseq0 ⊢ A ⊆ fi ⁡ A ∧ fi ⁡ A = ∅ → A = ∅
6 4 5 sylan ⊢ A ∈ V ∧ fi ⁡ A = ∅ → A = ∅
7 6 ex ⊢ A ∈ V → fi ⁡ A = ∅ → A = ∅
8 3 7 impbid2 ⊢ A ∈ V → A = ∅ ↔ fi ⁡ A = ∅