Metamath Proof Explorer


Theorem fliftel

Description: Elementhood in the relation F . (Contributed by Mario Carneiro, 23-Dec-2016)

Ref Expression
Hypotheses flift.1 ⊢ F = ran ⁡ x ∈ X ⟼ A B
flift.2 ⊢ φ ∧ x ∈ X → A ∈ R
flift.3 ⊢ φ ∧ x ∈ X → B ∈ S
Assertion fliftel ⊢ φ → C F D ↔ ∃ x ∈ X C = A ∧ D = B

Proof

Step Hyp Ref Expression
1 flift.1 ⊢ F = ran ⁡ x ∈ X ⟼ A B
2 flift.2 ⊢ φ ∧ x ∈ X → A ∈ R
3 flift.3 ⊢ φ ∧ x ∈ X → B ∈ S
4 df-br ⊢ C F D ↔ C D ∈ F
5 1 eleq2i ⊢ C D ∈ F ↔ C D ∈ ran ⁡ x ∈ X ⟼ A B
6 eqid ⊢ x ∈ X ⟼ A B = x ∈ X ⟼ A B
7 opex ⊢ A B ∈ V
8 6 7 elrnmpti ⊢ C D ∈ ran ⁡ x ∈ X ⟼ A B ↔ ∃ x ∈ X C D = A B
9 4 5 8 3bitri ⊢ C F D ↔ ∃ x ∈ X C D = A B
10 opthg2 ⊢ A ∈ R ∧ B ∈ S → C D = A B ↔ C = A ∧ D = B
11 2 3 10 syl2anc ⊢ φ ∧ x ∈ X → C D = A B ↔ C = A ∧ D = B
12 11 rexbidva ⊢ φ → ∃ x ∈ X C D = A B ↔ ∃ x ∈ X C = A ∧ D = B
13 9 12 bitrid ⊢ φ → C F D ↔ ∃ x ∈ X C = A ∧ D = B