Metamath Proof Explorer


Theorem fneu2

Description: There is exactly one value of a function. (Contributed by NM, 7-Nov-1995)

Ref Expression
Assertion fneu2 ⊢ F Fn A ∧ B ∈ A → ∃! y B y ∈ F

Proof

Step Hyp Ref Expression
1 fneu ⊢ F Fn A ∧ B ∈ A → ∃! y B F y
2 df-br ⊢ B F y ↔ B y ∈ F
3 2 eubii ⊢ ∃! y B F y ↔ ∃! y B y ∈ F
4 1 3 sylib ⊢ F Fn A ∧ B ∈ A → ∃! y B y ∈ F