Metamath Proof Explorer


Theorem frege53c

Description: Proposition 53 of Frege1879 p. 50. (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege53c ⊢ [˙A / x]˙ φ → A = B → [˙B / x]˙ φ

Proof

Step Hyp Ref Expression
1 ax-frege52c ⊢ A = B → [˙A / x]˙ φ → [˙B / x]˙ φ
2 ax-frege8 ⊢ A = B → [˙A / x]˙ φ → [˙B / x]˙ φ → [˙A / x]˙ φ → A = B → [˙B / x]˙ φ
3 1 2 ax-mp ⊢ [˙A / x]˙ φ → A = B → [˙B / x]˙ φ