Metamath Proof Explorer


Theorem freq12d

Description: Equality deduction for well-founded relations. (Contributed by Stefan O'Rear, 19-Jan-2015) (Proof shortened by Matthew House, 10-Sep-2025)

Ref Expression
Hypotheses freq12d.1 ⊢ φ → R = S
freq12d.2 ⊢ φ → A = B
Assertion freq12d ⊢ φ → R Fr A ↔ S Fr B

Proof

Step Hyp Ref Expression
1 freq12d.1 ⊢ φ → R = S
2 freq12d.2 ⊢ φ → A = B
3 freq1 ⊢ R = S → R Fr A ↔ S Fr A
4 freq2 ⊢ A = B → S Fr A ↔ S Fr B
5 3 4 sylan9bb ⊢ R = S ∧ A = B → R Fr A ↔ S Fr B
6 1 2 5 syl2anc ⊢ φ → R Fr A ↔ S Fr B