Metamath Proof Explorer


Theorem fvelimabd

Description: Deduction form of fvelimab . (Contributed by Stanislas Polu, 9-Mar-2020)

Ref Expression
Hypotheses fvelimabd.1 ⊢ φ → F Fn A
fvelimabd.2 ⊢ φ → B ⊆ A
Assertion fvelimabd ⊢ φ → C ∈ F B ↔ ∃ x ∈ B F ⁡ x = C

Proof

Step Hyp Ref Expression
1 fvelimabd.1 ⊢ φ → F Fn A
2 fvelimabd.2 ⊢ φ → B ⊆ A
3 fvelimab ⊢ F Fn A ∧ B ⊆ A → C ∈ F B ↔ ∃ x ∈ B F ⁡ x = C
4 1 2 3 syl2anc ⊢ φ → C ∈ F B ↔ ∃ x ∈ B F ⁡ x = C