Metamath Proof Explorer


Theorem fveq1

Description: Equality theorem for function value. (Contributed by NM, 29-Dec-1996)

Ref Expression
Assertion fveq1 F = G F A = G A

Proof

Step Hyp Ref Expression
1 breq F = G A F x A G x
2 1 iotabidv F = G ι x | A F x = ι x | A G x
3 df-fv F A = ι x | A F x
4 df-fv G A = ι x | A G x
5 2 3 4 3eqtr4g F = G F A = G A