Metamath Proof Explorer


Theorem fveq1

Description: Equality theorem for function value. (Contributed by NM, 29-Dec-1996)

Ref Expression
Assertion fveq1 ⊢ F = G → F ⁡ A = G ⁡ A

Proof

Step Hyp Ref Expression
1 breq ⊢ F = G → A F x ↔ A G x
2 1 iotabidv ⊢ F = G → ι x | A F x = ι x | A G x
3 df-fv ⊢ F ⁡ A = ι x | A F x
4 df-fv ⊢ G ⁡ A = ι x | A G x
5 2 3 4 3eqtr4g ⊢ F = G → F ⁡ A = G ⁡ A