Metamath Proof Explorer


Theorem fvifeq

Description: Equality of function values with conditional arguments, see also fvif . (Contributed by Alexander van der Vekens, 21-May-2018)

Ref Expression
Assertion fvifeq A=ifφBCFA=ifφFBFC

Proof

Step Hyp Ref Expression
1 fveq2 A=ifφBCFA=FifφBC
2 fvif FifφBC=ifφFBFC
3 1 2 eqtrdi A=ifφBCFA=ifφFBFC