Metamath Proof Explorer


Theorem ghmker

Description: The kernel of a homomorphism is a normal subgroup. (Contributed by Mario Carneiro, 4-Feb-2015)

Ref Expression
Hypothesis ghmker.1 ⊢ 0 ˙ = 0 T
Assertion ghmker ⊢ F ∈ S GrpHom T → F -1 0 ˙ ∈ NrmSGrp ⁡ S

Proof

Step Hyp Ref Expression
1 ghmker.1 ⊢ 0 ˙ = 0 T
2 ghmgrp2 ⊢ F ∈ S GrpHom T → T ∈ Grp
3 1 0nsg ⊢ T ∈ Grp → 0 ˙ ∈ NrmSGrp ⁡ T
4 2 3 syl ⊢ F ∈ S GrpHom T → 0 ˙ ∈ NrmSGrp ⁡ T
5 ghmnsgpreima ⊢ F ∈ S GrpHom T ∧ 0 ˙ ∈ NrmSGrp ⁡ T → F -1 0 ˙ ∈ NrmSGrp ⁡ S
6 4 5 mpdan ⊢ F ∈ S GrpHom T → F -1 0 ˙ ∈ NrmSGrp ⁡ S