Metamath Proof Explorer


Theorem ghmeqker

Description: Two source points map to the same destination point under a group homomorphism iff their difference belongs to the kernel. (Contributed by Stefan O'Rear, 31-Dec-2014)

Ref Expression
Hypotheses ghmeqker.b ⊢ B = Base S
ghmeqker.z ⊢ 0 ˙ = 0 T
ghmeqker.k ⊢ K = F -1 0 ˙
ghmeqker.m ⊢ - ˙ = - S
Assertion ghmeqker ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → F ⁡ U = F ⁡ V ↔ U - ˙ V ∈ K

Proof

Step Hyp Ref Expression
1 ghmeqker.b ⊢ B = Base S
2 ghmeqker.z ⊢ 0 ˙ = 0 T
3 ghmeqker.k ⊢ K = F -1 0 ˙
4 ghmeqker.m ⊢ - ˙ = - S
5 2 sneqi ⊢ 0 ˙ = 0 T
6 5 imaeq2i ⊢ F -1 0 ˙ = F -1 0 T
7 3 6 eqtri ⊢ K = F -1 0 T
8 7 eleq2i ⊢ U - ˙ V ∈ K ↔ U - ˙ V ∈ F -1 0 T
9 eqid ⊢ Base T = Base T
10 1 9 ghmf ⊢ F ∈ S GrpHom T → F : B ⟶ Base T
11 10 ffnd ⊢ F ∈ S GrpHom T → F Fn B
12 11 3ad2ant1 ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → F Fn B
13 fniniseg ⊢ F Fn B → U - ˙ V ∈ F -1 0 T ↔ U - ˙ V ∈ B ∧ F ⁡ U - ˙ V = 0 T
14 12 13 syl ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → U - ˙ V ∈ F -1 0 T ↔ U - ˙ V ∈ B ∧ F ⁡ U - ˙ V = 0 T
15 8 14 bitrid ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → U - ˙ V ∈ K ↔ U - ˙ V ∈ B ∧ F ⁡ U - ˙ V = 0 T
16 ghmgrp1 ⊢ F ∈ S GrpHom T → S ∈ Grp
17 1 4 grpsubcl ⊢ S ∈ Grp ∧ U ∈ B ∧ V ∈ B → U - ˙ V ∈ B
18 16 17 syl3an1 ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → U - ˙ V ∈ B
19 18 biantrurd ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → F ⁡ U - ˙ V = 0 T ↔ U - ˙ V ∈ B ∧ F ⁡ U - ˙ V = 0 T
20 eqid ⊢ - T = - T
21 1 4 20 ghmsub ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → F ⁡ U - ˙ V = F ⁡ U - T F ⁡ V
22 21 eqeq1d ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → F ⁡ U - ˙ V = 0 T ↔ F ⁡ U - T F ⁡ V = 0 T
23 19 22 bitr3d ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → U - ˙ V ∈ B ∧ F ⁡ U - ˙ V = 0 T ↔ F ⁡ U - T F ⁡ V = 0 T
24 ghmgrp2 ⊢ F ∈ S GrpHom T → T ∈ Grp
25 24 3ad2ant1 ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → T ∈ Grp
26 10 3ad2ant1 ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → F : B ⟶ Base T
27 simp2 ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → U ∈ B
28 26 27 ffvelcdmd ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → F ⁡ U ∈ Base T
29 simp3 ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → V ∈ B
30 26 29 ffvelcdmd ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → F ⁡ V ∈ Base T
31 eqid ⊢ 0 T = 0 T
32 9 31 20 grpsubeq0 ⊢ T ∈ Grp ∧ F ⁡ U ∈ Base T ∧ F ⁡ V ∈ Base T → F ⁡ U - T F ⁡ V = 0 T ↔ F ⁡ U = F ⁡ V
33 25 28 30 32 syl3anc ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → F ⁡ U - T F ⁡ V = 0 T ↔ F ⁡ U = F ⁡ V
34 15 23 33 3bitrrd ⊢ F ∈ S GrpHom T ∧ U ∈ B ∧ V ∈ B → F ⁡ U = F ⁡ V ↔ U - ˙ V ∈ K