Metamath Proof Explorer


Theorem griedg0prc

Description: The class of empty graphs (represented as ordered pairs) is a proper class. (Contributed by AV, 27-Dec-2020)

Ref Expression
Hypothesis griedg0prc.u ⊢ U = v e | e : ∅ ⟶ ∅
Assertion griedg0prc ⊢ U ∉ V

Proof

Step Hyp Ref Expression
1 griedg0prc.u ⊢ U = v e | e : ∅ ⟶ ∅
2 0ex ⊢ ∅ ∈ V
3 feq1 ⊢ e = ∅ → e : ∅ ⟶ ∅ ↔ ∅ : ∅ ⟶ ∅
4 f0 ⊢ ∅ : ∅ ⟶ ∅
5 2 3 4 ceqsexv2d ⊢ ∃ e e : ∅ ⟶ ∅
6 opabn1stprc ⊢ ∃ e e : ∅ ⟶ ∅ → v e | e : ∅ ⟶ ∅ ∉ V
7 5 6 ax-mp ⊢ v e | e : ∅ ⟶ ∅ ∉ V
8 neleq1 ⊢ U = v e | e : ∅ ⟶ ∅ → U ∉ V ↔ v e | e : ∅ ⟶ ∅ ∉ V
9 1 8 ax-mp ⊢ U ∉ V ↔ v e | e : ∅ ⟶ ∅ ∉ V
10 7 9 mpbir ⊢ U ∉ V