Metamath Proof Explorer


Theorem grpinv11

Description: The group inverse is one-to-one. (Contributed by NM, 22-Mar-2015) (Proof shortened by SN, 8-Jul-2025)

Ref Expression
Hypotheses grpinvinv.b ⊢ B = Base G
grpinvinv.n ⊢ N = inv g ⁡ G
grpinv11.g ⊢ φ → G ∈ Grp
grpinv11.x ⊢ φ → X ∈ B
grpinv11.y ⊢ φ → Y ∈ B
Assertion grpinv11 ⊢ φ → N ⁡ X = N ⁡ Y ↔ X = Y

Proof

Step Hyp Ref Expression
1 grpinvinv.b ⊢ B = Base G
2 grpinvinv.n ⊢ N = inv g ⁡ G
3 grpinv11.g ⊢ φ → G ∈ Grp
4 grpinv11.x ⊢ φ → X ∈ B
5 grpinv11.y ⊢ φ → Y ∈ B
6 fveq2 ⊢ N ⁡ X = N ⁡ Y → N ⁡ N ⁡ X = N ⁡ N ⁡ Y
7 1 2 grpinvinv ⊢ G ∈ Grp ∧ X ∈ B → N ⁡ N ⁡ X = X
8 3 4 7 syl2anc ⊢ φ → N ⁡ N ⁡ X = X
9 1 2 grpinvinv ⊢ G ∈ Grp ∧ Y ∈ B → N ⁡ N ⁡ Y = Y
10 3 5 9 syl2anc ⊢ φ → N ⁡ N ⁡ Y = Y
11 8 10 eqeq12d ⊢ φ → N ⁡ N ⁡ X = N ⁡ N ⁡ Y ↔ X = Y
12 6 11 imbitrid ⊢ φ → N ⁡ X = N ⁡ Y → X = Y
13 fveq2 ⊢ X = Y → N ⁡ X = N ⁡ Y
14 12 13 impbid1 ⊢ φ → N ⁡ X = N ⁡ Y ↔ X = Y