Metamath Proof Explorer


Theorem gsumadd

Description: The sum of two group sums. (Contributed by Mario Carneiro, 19-Dec-2014) (Revised by Mario Carneiro, 25-Apr-2016) (Revised by AV, 5-Jun-2019)

Ref Expression
Hypotheses gsumadd.b ⊢ B = Base G
gsumadd.z ⊢ 0 ˙ = 0 G
gsumadd.p ⊢ + ˙ = + G
gsumadd.g ⊢ φ → G ∈ CMnd
gsumadd.a ⊢ φ → A ∈ V
gsumadd.f ⊢ φ → F : A ⟶ B
gsumadd.h ⊢ φ → H : A ⟶ B
gsumadd.fn ⊢ φ → finSupp 0 ˙⁡ F
gsumadd.hn ⊢ φ → finSupp 0 ˙⁡ H
Assertion gsumadd ⊢ φ → ∑ G F + ˙ f H = ∑ G F + ˙ ∑ G H

Proof

Step Hyp Ref Expression
1 gsumadd.b ⊢ B = Base G
2 gsumadd.z ⊢ 0 ˙ = 0 G
3 gsumadd.p ⊢ + ˙ = + G
4 gsumadd.g ⊢ φ → G ∈ CMnd
5 gsumadd.a ⊢ φ → A ∈ V
6 gsumadd.f ⊢ φ → F : A ⟶ B
7 gsumadd.h ⊢ φ → H : A ⟶ B
8 gsumadd.fn ⊢ φ → finSupp 0 ˙⁡ F
9 gsumadd.hn ⊢ φ → finSupp 0 ˙⁡ H
10 eqid ⊢ Cntz ⁡ G = Cntz ⁡ G
11 cmnmnd ⊢ G ∈ CMnd → G ∈ Mnd
12 4 11 syl ⊢ φ → G ∈ Mnd
13 1 submid ⊢ G ∈ Mnd → B ∈ SubMnd ⁡ G
14 12 13 syl ⊢ φ → B ∈ SubMnd ⁡ G
15 ssid ⊢ B ⊆ B
16 1 10 cntzcmn ⊢ G ∈ CMnd ∧ B ⊆ B → Cntz ⁡ G ⁡ B = B
17 4 15 16 sylancl ⊢ φ → Cntz ⁡ G ⁡ B = B
18 15 17 sseqtrrid ⊢ φ → B ⊆ Cntz ⁡ G ⁡ B
19 1 2 3 10 12 5 8 9 14 18 6 7 gsumzadd ⊢ φ → ∑ G F + ˙ f H = ∑ G F + ˙ ∑ G H