Metamath Proof Explorer


Theorem ififcom

Description: Commute two nested conditionals. (Contributed by Thierry Arnoux, 4-May-2026)

Ref Expression
Assertion ififcom if φ if ψ A B B = if ψ if φ A B B

Proof

Step Hyp Ref Expression
1 ancom φ ψ ψ φ
2 ifbi φ ψ ψ φ if φ ψ A B = if ψ φ A B
3 1 2 ax-mp if φ ψ A B = if ψ φ A B
4 ifan if φ ψ A B = if φ if ψ A B B
5 ifan if ψ φ A B = if ψ if φ A B B
6 3 4 5 3eqtr3i if φ if ψ A B B = if ψ if φ A B B