Metamath Proof Explorer


Theorem inagne3

Description: Deduce inequality from the in-angle relation. (Contributed by Thierry Arnoux, 29-Oct-2021)

Ref Expression
Hypotheses isinag.p ⊢ P = Base G
isinag.i ⊢ I = Itv ⁡ G
isinag.k ⊢ K = hl 𝒢 ⁡ G
isinag.x ⊢ φ → X ∈ P
isinag.a ⊢ φ → A ∈ P
isinag.b ⊢ φ → B ∈ P
isinag.c ⊢ φ → C ∈ P
inagflat.g ⊢ φ → G ∈ 𝒢 Tarski
inagswap.1 ⊢ φ → X ∈ 𝒢 ∠ ⁡ G ⟨“ ABC ”⟩
Assertion inagne3 ⊢ φ → X ≠ B

Proof

Step Hyp Ref Expression
1 isinag.p ⊢ P = Base G
2 isinag.i ⊢ I = Itv ⁡ G
3 isinag.k ⊢ K = hl 𝒢 ⁡ G
4 isinag.x ⊢ φ → X ∈ P
5 isinag.a ⊢ φ → A ∈ P
6 isinag.b ⊢ φ → B ∈ P
7 isinag.c ⊢ φ → C ∈ P
8 inagflat.g ⊢ φ → G ∈ 𝒢 Tarski
9 inagswap.1 ⊢ φ → X ∈ 𝒢 ∠ ⁡ G ⟨“ ABC ”⟩
10 1 2 3 4 5 6 7 8 isinag ⊢ φ → X ∈ 𝒢 ∠ ⁡ G ⟨“ ABC ”⟩ ↔ A ≠ B ∧ C ≠ B ∧ X ≠ B ∧ ∃ x ∈ P x ∈ A I C ∧ x = B ∨ x K ⁡ B X
11 9 10 mpbid ⊢ φ → A ≠ B ∧ C ≠ B ∧ X ≠ B ∧ ∃ x ∈ P x ∈ A I C ∧ x = B ∨ x K ⁡ B X
12 11 simpld ⊢ φ → A ≠ B ∧ C ≠ B ∧ X ≠ B
13 12 simp3d ⊢ φ → X ≠ B