Metamath Proof Explorer


Theorem ineq12d

Description: Equality deduction for intersection of two classes. (Contributed by NM, 24-Jun-2004) (Proof shortened by Andrew Salmon, 26-Jun-2011)

Ref Expression
Hypotheses ineq1d.1 φ A = B
ineq12d.2 φ C = D
Assertion ineq12d φ A C = B D

Proof

Step Hyp Ref Expression
1 ineq1d.1 φ A = B
2 ineq12d.2 φ C = D
3 ineq12 A = B C = D A C = B D
4 1 2 3 syl2anc φ A C = B D