Metamath Proof Explorer
Description: Equality deduction for intersection of two classes. (Contributed by NM, 24-Jun-2004) (Proof shortened by Andrew Salmon, 26-Jun-2011)
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Ref |
Expression |
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Hypotheses |
ineq1d.1 |
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|
ineq12d.2 |
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Assertion |
ineq12d |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
ineq1d.1 |
|
2 |
|
ineq12d.2 |
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3 |
|
ineq12 |
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4 |
1 2 3
|
syl2anc |
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