Metamath Proof Explorer


Theorem ineqcomi

Description: Disjointness inference (when C = (/) ), inference form of ineqcom . (Contributed by Peter Mazsa, 26-Mar-2017)

Ref Expression
Hypothesis ineqcomi.1 A B = C
Assertion ineqcomi B A = C

Proof

Step Hyp Ref Expression
1 ineqcomi.1 A B = C
2 ineqcom A B = C B A = C
3 1 2 mpbi B A = C