Metamath Proof Explorer


Theorem inxpss2

Description: Two ways to say that intersections with Cartesian products are in a subclass relation. (Contributed by Peter Mazsa, 8-Mar-2019)

Ref Expression
Assertion inxpss2 ⊢ R ∩ A × B ⊆ S ∩ A × B ↔ ∀ x ∈ A ∀ y ∈ B x R y → x S y

Proof

Step Hyp Ref Expression
1 relinxp ⊢ Rel ⁡ R ∩ A × B
2 ssrel3 ⊢ Rel ⁡ R ∩ A × B → R ∩ A × B ⊆ S ∩ A × B ↔ ∀ x ∀ y x R ∩ A × B y → x S ∩ A × B y
3 1 2 ax-mp ⊢ R ∩ A × B ⊆ S ∩ A × B ↔ ∀ x ∀ y x R ∩ A × B y → x S ∩ A × B y
4 inxpss3 ⊢ ∀ x ∀ y x R ∩ A × B y → x S ∩ A × B y ↔ ∀ x ∈ A ∀ y ∈ B x R y → x S y
5 3 4 bitri ⊢ R ∩ A × B ⊆ S ∩ A × B ↔ ∀ x ∈ A ∀ y ∈ B x R y → x S y