Metamath Proof Explorer


Theorem islvec

Description: The predicate "is a left vector space". (Contributed by NM, 11-Nov-2013)

Ref Expression
Hypothesis islvec.1 ⊢ F = Scalar ⁡ W
Assertion islvec ⊢ W ∈ LVec ↔ W ∈ LMod ∧ F ∈ DivRing

Proof

Step Hyp Ref Expression
1 islvec.1 ⊢ F = Scalar ⁡ W
2 fveq2 ⊢ f = W → Scalar ⁡ f = Scalar ⁡ W
3 2 1 eqtr4di ⊢ f = W → Scalar ⁡ f = F
4 3 eleq1d ⊢ f = W → Scalar ⁡ f ∈ DivRing ↔ F ∈ DivRing
5 df-lvec ⊢ LVec = f ∈ LMod | Scalar ⁡ f ∈ DivRing
6 4 5 elrab2 ⊢ W ∈ LVec ↔ W ∈ LMod ∧ F ∈ DivRing