Metamath Proof Explorer


Theorem joinlmulsubmuld

Description: Join AB-CB into (A-C) on LHS. (Contributed by David A. Wheeler, 15-Oct-2018)

Ref Expression
Hypotheses joinlmulsubmuld.1 ⊢ φ → A ∈ ℂ
joinlmulsubmuld.2 ⊢ φ → B ∈ ℂ
joinlmulsubmuld.3 ⊢ φ → C ∈ ℂ
joinlmulsubmuld.4 ⊢ φ → A ⁢ B − C ⁢ B = D
Assertion joinlmulsubmuld ⊢ φ → A − C ⁢ B = D

Proof

Step Hyp Ref Expression
1 joinlmulsubmuld.1 ⊢ φ → A ∈ ℂ
2 joinlmulsubmuld.2 ⊢ φ → B ∈ ℂ
3 joinlmulsubmuld.3 ⊢ φ → C ∈ ℂ
4 joinlmulsubmuld.4 ⊢ φ → A ⁢ B − C ⁢ B = D
5 1 3 2 subdird ⊢ φ → A − C ⁢ B = A ⁢ B − C ⁢ B
6 5 4 eqtrd ⊢ φ → A − C ⁢ B = D