Metamath Proof Explorer
Description: Every vector space has a basis. This theorem is an AC equivalent.
(Contributed by Mario Carneiro, 25-Jun-2014)
|
|
Ref |
Expression |
|
Hypothesis |
lbsex.j |
|
|
Assertion |
lbsex |
|
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
lbsex.j |
|
| 2 |
|
axac3 |
|
| 3 |
1
|
lbsexg |
|
| 4 |
2 3
|
mpan |
|