Metamath Proof Explorer


Theorem lnopco0i

Description: The composition of a linear operator with one whose norm is zero. (Contributed by NM, 10-Mar-2006) (New usage is discouraged.)

Ref Expression
Hypotheses lnopco.1 ⊢ S ∈ LinOp
lnopco.2 ⊢ T ∈ LinOp
Assertion lnopco0i ⊢ norm op ⁡ T = 0 → norm op ⁡ S ∘ T = 0

Proof

Step Hyp Ref Expression
1 lnopco.1 ⊢ S ∈ LinOp
2 lnopco.2 ⊢ T ∈ LinOp
3 coeq2 ⊢ T = 0 hop → S ∘ T = S ∘ 0 hop
4 0lnop ⊢ 0 hop ∈ LinOp
5 1 4 lnopcoi ⊢ S ∘ 0 hop ∈ LinOp
6 5 lnopfi ⊢ S ∘ 0 hop : ℋ ⟶ ℋ
7 ffn ⊢ S ∘ 0 hop : ℋ ⟶ ℋ → S ∘ 0 hop Fn ℋ
8 6 7 ax-mp ⊢ S ∘ 0 hop Fn ℋ
9 ho0f ⊢ 0 hop : ℋ ⟶ ℋ
10 ffn ⊢ 0 hop : ℋ ⟶ ℋ → 0 hop Fn ℋ
11 9 10 ax-mp ⊢ 0 hop Fn ℋ
12 eqfnfv ⊢ S ∘ 0 hop Fn ℋ ∧ 0 hop Fn ℋ → S ∘ 0 hop = 0 hop ↔ ∀ x ∈ ℋ S ∘ 0 hop ⁡ x = 0 hop ⁡ x
13 8 11 12 mp2an ⊢ S ∘ 0 hop = 0 hop ↔ ∀ x ∈ ℋ S ∘ 0 hop ⁡ x = 0 hop ⁡ x
14 ho0val ⊢ x ∈ ℋ → 0 hop ⁡ x = 0 ℎ
15 14 fveq2d ⊢ x ∈ ℋ → S ⁡ 0 hop ⁡ x = S ⁡ 0 ℎ
16 1 lnop0i ⊢ S ⁡ 0 ℎ = 0 ℎ
17 15 16 eqtrdi ⊢ x ∈ ℋ → S ⁡ 0 hop ⁡ x = 0 ℎ
18 1 lnopfi ⊢ S : ℋ ⟶ ℋ
19 18 9 hocoi ⊢ x ∈ ℋ → S ∘ 0 hop ⁡ x = S ⁡ 0 hop ⁡ x
20 17 19 14 3eqtr4d ⊢ x ∈ ℋ → S ∘ 0 hop ⁡ x = 0 hop ⁡ x
21 13 20 mprgbir ⊢ S ∘ 0 hop = 0 hop
22 3 21 eqtrdi ⊢ T = 0 hop → S ∘ T = 0 hop
23 2 nmlnop0iHIL ⊢ norm op ⁡ T = 0 ↔ T = 0 hop
24 1 2 lnopcoi ⊢ S ∘ T ∈ LinOp
25 24 nmlnop0iHIL ⊢ norm op ⁡ S ∘ T = 0 ↔ S ∘ T = 0 hop
26 22 23 25 3imtr4i ⊢ norm op ⁡ T = 0 → norm op ⁡ S ∘ T = 0