Metamath Proof Explorer


Theorem lsmdisj2r

Description: Association of the disjointness constraint in a subgroup sum. (Contributed by Mario Carneiro, 22-Apr-2016)

Ref Expression
Hypotheses lsmcntz.p ⊢ ⊕ ˙ = LSSum ⁡ G
lsmcntz.s ⊢ φ → S ∈ SubGrp ⁡ G
lsmcntz.t ⊢ φ → T ∈ SubGrp ⁡ G
lsmcntz.u ⊢ φ → U ∈ SubGrp ⁡ G
lsmdisj.o ⊢ 0 ˙ = 0 G
lsmdisjr.i ⊢ φ → S ∩ T ⊕ ˙ U = 0 ˙
lsmdisj2r.i ⊢ φ → T ∩ U = 0 ˙
Assertion lsmdisj2r ⊢ φ → S ⊕ ˙ U ∩ T = 0 ˙

Proof

Step Hyp Ref Expression
1 lsmcntz.p ⊢ ⊕ ˙ = LSSum ⁡ G
2 lsmcntz.s ⊢ φ → S ∈ SubGrp ⁡ G
3 lsmcntz.t ⊢ φ → T ∈ SubGrp ⁡ G
4 lsmcntz.u ⊢ φ → U ∈ SubGrp ⁡ G
5 lsmdisj.o ⊢ 0 ˙ = 0 G
6 lsmdisjr.i ⊢ φ → S ∩ T ⊕ ˙ U = 0 ˙
7 lsmdisj2r.i ⊢ φ → T ∩ U = 0 ˙
8 eqid ⊢ opp 𝑔 ⁡ G = opp 𝑔 ⁡ G
9 8 1 oppglsm ⊢ U LSSum ⁡ opp 𝑔 ⁡ G S = S ⊕ ˙ U
10 9 ineq2i ⊢ T ∩ U LSSum ⁡ opp 𝑔 ⁡ G S = T ∩ S ⊕ ˙ U
11 incom ⊢ T ∩ S ⊕ ˙ U = S ⊕ ˙ U ∩ T
12 10 11 eqtri ⊢ T ∩ U LSSum ⁡ opp 𝑔 ⁡ G S = S ⊕ ˙ U ∩ T
13 eqid ⊢ LSSum ⁡ opp 𝑔 ⁡ G = LSSum ⁡ opp 𝑔 ⁡ G
14 8 oppgsubg ⊢ SubGrp ⁡ G = SubGrp ⁡ opp 𝑔 ⁡ G
15 4 14 eleqtrdi ⊢ φ → U ∈ SubGrp ⁡ opp 𝑔 ⁡ G
16 3 14 eleqtrdi ⊢ φ → T ∈ SubGrp ⁡ opp 𝑔 ⁡ G
17 2 14 eleqtrdi ⊢ φ → S ∈ SubGrp ⁡ opp 𝑔 ⁡ G
18 8 5 oppgid ⊢ 0 ˙ = 0 opp 𝑔 ⁡ G
19 8 1 oppglsm ⊢ U LSSum ⁡ opp 𝑔 ⁡ G T = T ⊕ ˙ U
20 19 ineq1i ⊢ U LSSum ⁡ opp 𝑔 ⁡ G T ∩ S = T ⊕ ˙ U ∩ S
21 incom ⊢ T ⊕ ˙ U ∩ S = S ∩ T ⊕ ˙ U
22 20 21 eqtri ⊢ U LSSum ⁡ opp 𝑔 ⁡ G T ∩ S = S ∩ T ⊕ ˙ U
23 22 6 eqtrid ⊢ φ → U LSSum ⁡ opp 𝑔 ⁡ G T ∩ S = 0 ˙
24 incom ⊢ T ∩ U = U ∩ T
25 24 7 eqtr3id ⊢ φ → U ∩ T = 0 ˙
26 13 15 16 17 18 23 25 lsmdisj2 ⊢ φ → T ∩ U LSSum ⁡ opp 𝑔 ⁡ G S = 0 ˙
27 12 26 eqtr3id ⊢ φ → S ⊕ ˙ U ∩ T = 0 ˙