Metamath Proof Explorer


Theorem lsmelvalmi

Description: Membership of vector subtraction in subgroup sum. (Contributed by NM, 27-Apr-2015) (Revised by Mario Carneiro, 19-Apr-2016)

Ref Expression
Hypotheses lsmelvalm.m ⊢ - ˙ = - G
lsmelvalm.p ⊢ ⊕ ˙ = LSSum ⁡ G
lsmelvalm.t ⊢ φ → T ∈ SubGrp ⁡ G
lsmelvalm.u ⊢ φ → U ∈ SubGrp ⁡ G
lsmelvalmi.x ⊢ φ → X ∈ T
lsmelvalmi.y ⊢ φ → Y ∈ U
Assertion lsmelvalmi ⊢ φ → X - ˙ Y ∈ T ⊕ ˙ U

Proof

Step Hyp Ref Expression
1 lsmelvalm.m ⊢ - ˙ = - G
2 lsmelvalm.p ⊢ ⊕ ˙ = LSSum ⁡ G
3 lsmelvalm.t ⊢ φ → T ∈ SubGrp ⁡ G
4 lsmelvalm.u ⊢ φ → U ∈ SubGrp ⁡ G
5 lsmelvalmi.x ⊢ φ → X ∈ T
6 lsmelvalmi.y ⊢ φ → Y ∈ U
7 eqidd ⊢ φ → X - ˙ Y = X - ˙ Y
8 rspceov ⊢ X ∈ T ∧ Y ∈ U ∧ X - ˙ Y = X - ˙ Y → ∃ x ∈ T ∃ y ∈ U X - ˙ Y = x - ˙ y
9 5 6 7 8 syl3anc ⊢ φ → ∃ x ∈ T ∃ y ∈ U X - ˙ Y = x - ˙ y
10 1 2 3 4 lsmelvalm ⊢ φ → X - ˙ Y ∈ T ⊕ ˙ U ↔ ∃ x ∈ T ∃ y ∈ U X - ˙ Y = x - ˙ y
11 9 10 mpbird ⊢ φ → X - ˙ Y ∈ T ⊕ ˙ U