Metamath Proof Explorer


Theorem lspsnne2

Description: Two ways to express that vectors have different spans. (Contributed by NM, 20-May-2015)

Ref Expression
Hypotheses lspsnne2.v ⊢ V = Base W
lspsnne2.n ⊢ N = LSpan ⁡ W
lspsnne2.w ⊢ φ → W ∈ LMod
lspsnne2.x ⊢ φ → X ∈ V
lspsnne2.y ⊢ φ → Y ∈ V
lspsnne2.e ⊢ φ → ¬ X ∈ N ⁡ Y
Assertion lspsnne2 ⊢ φ → N ⁡ X ≠ N ⁡ Y

Proof

Step Hyp Ref Expression
1 lspsnne2.v ⊢ V = Base W
2 lspsnne2.n ⊢ N = LSpan ⁡ W
3 lspsnne2.w ⊢ φ → W ∈ LMod
4 lspsnne2.x ⊢ φ → X ∈ V
5 lspsnne2.y ⊢ φ → Y ∈ V
6 lspsnne2.e ⊢ φ → ¬ X ∈ N ⁡ Y
7 eqimss ⊢ N ⁡ X = N ⁡ Y → N ⁡ X ⊆ N ⁡ Y
8 eqid ⊢ LSubSp ⁡ W = LSubSp ⁡ W
9 1 8 2 lspsncl ⊢ W ∈ LMod ∧ Y ∈ V → N ⁡ Y ∈ LSubSp ⁡ W
10 3 5 9 syl2anc ⊢ φ → N ⁡ Y ∈ LSubSp ⁡ W
11 1 8 2 3 10 4 ellspsn5b ⊢ φ → X ∈ N ⁡ Y ↔ N ⁡ X ⊆ N ⁡ Y
12 7 11 imbitrrid ⊢ φ → N ⁡ X = N ⁡ Y → X ∈ N ⁡ Y
13 12 necon3bd ⊢ φ → ¬ X ∈ N ⁡ Y → N ⁡ X ≠ N ⁡ Y
14 6 13 mpd ⊢ φ → N ⁡ X ≠ N ⁡ Y