Metamath Proof Explorer


Theorem ltrnnid

Description: If a lattice translation is not the identity, then there is an atom not under the fiducial co-atom W and not equal to its translation. (Contributed by NM, 24-May-2012)

Ref Expression
Hypotheses ltrneq.b ⊢ B = Base K
ltrneq.l ⊢ ≤ ˙ = ≤ K
ltrneq.a ⊢ A = Atoms ⁡ K
ltrneq.h ⊢ H = LHyp ⁡ K
ltrneq.t ⊢ T = LTrn ⁡ K ⁡ W
Assertion ltrnnid ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → ∃ p ∈ A ¬ p ≤ ˙ W ∧ F ⁡ p ≠ p

Proof

Step Hyp Ref Expression
1 ltrneq.b ⊢ B = Base K
2 ltrneq.l ⊢ ≤ ˙ = ≤ K
3 ltrneq.a ⊢ A = Atoms ⁡ K
4 ltrneq.h ⊢ H = LHyp ⁡ K
5 ltrneq.t ⊢ T = LTrn ⁡ K ⁡ W
6 ralinexa ⊢ ∀ p ∈ A ¬ p ≤ ˙ W → ¬ F ⁡ p ≠ p ↔ ¬ ∃ p ∈ A ¬ p ≤ ˙ W ∧ F ⁡ p ≠ p
7 nne ⊢ ¬ F ⁡ p ≠ p ↔ F ⁡ p = p
8 7 biimpi ⊢ ¬ F ⁡ p ≠ p → F ⁡ p = p
9 8 imim2i ⊢ ¬ p ≤ ˙ W → ¬ F ⁡ p ≠ p → ¬ p ≤ ˙ W → F ⁡ p = p
10 9 ralimi ⊢ ∀ p ∈ A ¬ p ≤ ˙ W → ¬ F ⁡ p ≠ p → ∀ p ∈ A ¬ p ≤ ˙ W → F ⁡ p = p
11 6 10 sylbir ⊢ ¬ ∃ p ∈ A ¬ p ≤ ˙ W ∧ F ⁡ p ≠ p → ∀ p ∈ A ¬ p ≤ ˙ W → F ⁡ p = p
12 1 2 3 4 5 ltrnid ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → ∀ p ∈ A ¬ p ≤ ˙ W → F ⁡ p = p ↔ F = I ↾ B
13 11 12 imbitrid ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → ¬ ∃ p ∈ A ¬ p ≤ ˙ W ∧ F ⁡ p ≠ p → F = I ↾ B
14 13 necon1ad ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F ≠ I ↾ B → ∃ p ∈ A ¬ p ≤ ˙ W ∧ F ⁡ p ≠ p
15 14 3impia ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → ∃ p ∈ A ¬ p ≤ ˙ W ∧ F ⁡ p ≠ p