Metamath Proof Explorer


Theorem mapdpglem4N

Description: Lemma for mapdpg . (Contributed by NM, 20-Mar-2015) (New usage is discouraged.)

Ref Expression
Hypotheses mapdpglem.h H = LHyp K
mapdpglem.m M = mapd K W
mapdpglem.u U = DVecH K W
mapdpglem.v V = Base U
mapdpglem.s - ˙ = - U
mapdpglem.n N = LSpan U
mapdpglem.c C = LCDual K W
mapdpglem.k φ K HL W H
mapdpglem.x φ X V
mapdpglem.y φ Y V
mapdpglem1.p ˙ = LSSum C
mapdpglem2.j J = LSpan C
mapdpglem3.f F = Base C
mapdpglem3.te φ t M N X ˙ M N Y
mapdpglem3.a A = Scalar U
mapdpglem3.b B = Base A
mapdpglem3.t · ˙ = C
mapdpglem3.r R = - C
mapdpglem3.g φ G F
mapdpglem3.e φ M N X = J G
mapdpglem4.q Q = 0 U
mapdpglem.ne φ N X N Y
Assertion mapdpglem4N φ X - ˙ Y Q

Proof

Step Hyp Ref Expression
1 mapdpglem.h H = LHyp K
2 mapdpglem.m M = mapd K W
3 mapdpglem.u U = DVecH K W
4 mapdpglem.v V = Base U
5 mapdpglem.s - ˙ = - U
6 mapdpglem.n N = LSpan U
7 mapdpglem.c C = LCDual K W
8 mapdpglem.k φ K HL W H
9 mapdpglem.x φ X V
10 mapdpglem.y φ Y V
11 mapdpglem1.p ˙ = LSSum C
12 mapdpglem2.j J = LSpan C
13 mapdpglem3.f F = Base C
14 mapdpglem3.te φ t M N X ˙ M N Y
15 mapdpglem3.a A = Scalar U
16 mapdpglem3.b B = Base A
17 mapdpglem3.t · ˙ = C
18 mapdpglem3.r R = - C
19 mapdpglem3.g φ G F
20 mapdpglem3.e φ M N X = J G
21 mapdpglem4.q Q = 0 U
22 mapdpglem.ne φ N X N Y
23 1 3 8 dvhlmod φ U LMod
24 4 21 5 23 9 10 22 lspsnsubn0 φ X - ˙ Y Q