Metamath Proof Explorer


Theorem midcl

Description: Closure of the midpoint. (Contributed by Thierry Arnoux, 1-Dec-2019)

Ref Expression
Hypotheses ismid.p ⊢ P = Base G
ismid.d ⊢ - ˙ = dist ⁡ G
ismid.i ⊢ I = Itv ⁡ G
ismid.g ⊢ φ → G ∈ 𝒢 Tarski
ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
midcl.1 ⊢ φ → A ∈ P
midcl.2 ⊢ φ → B ∈ P
Assertion midcl ⊢ φ → A mid 𝒢 ⁡ G B ∈ P

Proof

Step Hyp Ref Expression
1 ismid.p ⊢ P = Base G
2 ismid.d ⊢ - ˙ = dist ⁡ G
3 ismid.i ⊢ I = Itv ⁡ G
4 ismid.g ⊢ φ → G ∈ 𝒢 Tarski
5 ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
6 midcl.1 ⊢ φ → A ∈ P
7 midcl.2 ⊢ φ → B ∈ P
8 1 2 3 4 5 midf ⊢ φ → mid 𝒢 ⁡ G : P × P ⟶ P
9 8 6 7 fovcdmd ⊢ φ → A mid 𝒢 ⁡ G B ∈ P