Metamath Proof Explorer


Theorem ismidb

Description: Property of the midpoint. (Contributed by Thierry Arnoux, 1-Dec-2019)

Ref Expression
Hypotheses ismid.p ⊢ P = Base G
ismid.d ⊢ - ˙ = dist ⁡ G
ismid.i ⊢ I = Itv ⁡ G
ismid.g ⊢ φ → G ∈ 𝒢 Tarski
ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
midcl.1 ⊢ φ → A ∈ P
midcl.2 ⊢ φ → B ∈ P
ismidb.s ⊢ S = pInv 𝒢 ⁡ G
ismidb.m ⊢ φ → M ∈ P
Assertion ismidb ⊢ φ → B = S ⁡ M ⁡ A ↔ A mid 𝒢 ⁡ G B = M

Proof

Step Hyp Ref Expression
1 ismid.p ⊢ P = Base G
2 ismid.d ⊢ - ˙ = dist ⁡ G
3 ismid.i ⊢ I = Itv ⁡ G
4 ismid.g ⊢ φ → G ∈ 𝒢 Tarski
5 ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
6 midcl.1 ⊢ φ → A ∈ P
7 midcl.2 ⊢ φ → B ∈ P
8 ismidb.s ⊢ S = pInv 𝒢 ⁡ G
9 ismidb.m ⊢ φ → M ∈ P
10 eqid ⊢ Line 𝒢 ⁡ G = Line 𝒢 ⁡ G
11 1 2 3 10 4 8 6 7 5 mideu ⊢ φ → ∃! m ∈ P B = S ⁡ m ⁡ A
12 fveq2 ⊢ m = M → S ⁡ m = S ⁡ M
13 12 fveq1d ⊢ m = M → S ⁡ m ⁡ A = S ⁡ M ⁡ A
14 13 eqeq2d ⊢ m = M → B = S ⁡ m ⁡ A ↔ B = S ⁡ M ⁡ A
15 14 riota2 ⊢ M ∈ P ∧ ∃! m ∈ P B = S ⁡ m ⁡ A → B = S ⁡ M ⁡ A ↔ ι m ∈ P | B = S ⁡ m ⁡ A = M
16 9 11 15 syl2anc ⊢ φ → B = S ⁡ M ⁡ A ↔ ι m ∈ P | B = S ⁡ m ⁡ A = M
17 df-mid ⊢ mid 𝒢 = g ∈ V ⟼ a ∈ Base g , b ∈ Base g ⟼ ι m ∈ Base g | b = pInv 𝒢 ⁡ g ⁡ m ⁡ a
18 fveq2 ⊢ g = G → Base g = Base G
19 18 1 eqtr4di ⊢ g = G → Base g = P
20 fveq2 ⊢ g = G → pInv 𝒢 ⁡ g = pInv 𝒢 ⁡ G
21 20 8 eqtr4di ⊢ g = G → pInv 𝒢 ⁡ g = S
22 21 fveq1d ⊢ g = G → pInv 𝒢 ⁡ g ⁡ m = S ⁡ m
23 22 fveq1d ⊢ g = G → pInv 𝒢 ⁡ g ⁡ m ⁡ a = S ⁡ m ⁡ a
24 23 eqeq2d ⊢ g = G → b = pInv 𝒢 ⁡ g ⁡ m ⁡ a ↔ b = S ⁡ m ⁡ a
25 19 24 riotaeqbidv ⊢ g = G → ι m ∈ Base g | b = pInv 𝒢 ⁡ g ⁡ m ⁡ a = ι m ∈ P | b = S ⁡ m ⁡ a
26 19 19 25 mpoeq123dv ⊢ g = G → a ∈ Base g , b ∈ Base g ⟼ ι m ∈ Base g | b = pInv 𝒢 ⁡ g ⁡ m ⁡ a = a ∈ P , b ∈ P ⟼ ι m ∈ P | b = S ⁡ m ⁡ a
27 4 elexd ⊢ φ → G ∈ V
28 1 fvexi ⊢ P ∈ V
29 28 28 mpoex ⊢ a ∈ P , b ∈ P ⟼ ι m ∈ P | b = S ⁡ m ⁡ a ∈ V
30 29 a1i ⊢ φ → a ∈ P , b ∈ P ⟼ ι m ∈ P | b = S ⁡ m ⁡ a ∈ V
31 17 26 27 30 fvmptd3 ⊢ φ → mid 𝒢 ⁡ G = a ∈ P , b ∈ P ⟼ ι m ∈ P | b = S ⁡ m ⁡ a
32 simprr ⊢ φ ∧ a = A ∧ b = B → b = B
33 simprl ⊢ φ ∧ a = A ∧ b = B → a = A
34 33 fveq2d ⊢ φ ∧ a = A ∧ b = B → S ⁡ m ⁡ a = S ⁡ m ⁡ A
35 32 34 eqeq12d ⊢ φ ∧ a = A ∧ b = B → b = S ⁡ m ⁡ a ↔ B = S ⁡ m ⁡ A
36 35 riotabidv ⊢ φ ∧ a = A ∧ b = B → ι m ∈ P | b = S ⁡ m ⁡ a = ι m ∈ P | B = S ⁡ m ⁡ A
37 riotacl ⊢ ∃! m ∈ P B = S ⁡ m ⁡ A → ι m ∈ P | B = S ⁡ m ⁡ A ∈ P
38 11 37 syl ⊢ φ → ι m ∈ P | B = S ⁡ m ⁡ A ∈ P
39 31 36 6 7 38 ovmpod ⊢ φ → A mid 𝒢 ⁡ G B = ι m ∈ P | B = S ⁡ m ⁡ A
40 39 eqeq1d ⊢ φ → A mid 𝒢 ⁡ G B = M ↔ ι m ∈ P | B = S ⁡ m ⁡ A = M
41 16 40 bitr4d ⊢ φ → B = S ⁡ M ⁡ A ↔ A mid 𝒢 ⁡ G B = M