Metamath Proof Explorer


Theorem mod2xnegi

Description: Version of mod2xi where A ^ B does not equal K (mod N ) but instead the negative of K (mod N ). (Contributed by Mario Carneiro, 21-Feb-2014)

Ref Expression
Hypotheses mod2xnegi.1 ⊢ A ∈ ℕ
mod2xnegi.2 ⊢ B ∈ ℕ 0
mod2xnegi.3 ⊢ D ∈ ℤ
mod2xnegi.4 ⊢ K ∈ ℕ
mod2xnegi.5 ⊢ M ∈ ℕ 0
mod2xnegi.6 ⊢ L ∈ ℕ 0
mod2xnegi.10 ⊢ A B mod N = L mod N
mod2xnegi.7 ⊢ 2 ⁢ B = E
mod2xnegi.8 ⊢ L + K = N
mod2xnegi.9 ⊢ D ⋅ N + M = K ⁢ K
Assertion mod2xnegi ⊢ A E mod N = M mod N

Proof

Step Hyp Ref Expression
1 mod2xnegi.1 ⊢ A ∈ ℕ
2 mod2xnegi.2 ⊢ B ∈ ℕ 0
3 mod2xnegi.3 ⊢ D ∈ ℤ
4 mod2xnegi.4 ⊢ K ∈ ℕ
5 mod2xnegi.5 ⊢ M ∈ ℕ 0
6 mod2xnegi.6 ⊢ L ∈ ℕ 0
7 mod2xnegi.10 ⊢ A B mod N = L mod N
8 mod2xnegi.7 ⊢ 2 ⁢ B = E
9 mod2xnegi.8 ⊢ L + K = N
10 mod2xnegi.9 ⊢ D ⋅ N + M = K ⁢ K
11 nn0nnaddcl ⊢ L ∈ ℕ 0 ∧ K ∈ ℕ → L + K ∈ ℕ
12 6 4 11 mp2an ⊢ L + K ∈ ℕ
13 9 12 eqeltrri ⊢ N ∈ ℕ
14 13 nnzi ⊢ N ∈ ℤ
15 zaddcl ⊢ N ∈ ℤ ∧ D ∈ ℤ → N + D ∈ ℤ
16 14 3 15 mp2an ⊢ N + D ∈ ℤ
17 4 nnnn0i ⊢ K ∈ ℕ 0
18 17 17 nn0addcli ⊢ K + K ∈ ℕ 0
19 18 nn0zi ⊢ K + K ∈ ℤ
20 zsubcl ⊢ N + D ∈ ℤ ∧ K + K ∈ ℤ → N + D - K + K ∈ ℤ
21 16 19 20 mp2an ⊢ N + D - K + K ∈ ℤ
22 13 nncni ⊢ N ∈ ℂ
23 zcn ⊢ D ∈ ℤ → D ∈ ℂ
24 3 23 ax-mp ⊢ D ∈ ℂ
25 22 24 addcli ⊢ N + D ∈ ℂ
26 4 nncni ⊢ K ∈ ℂ
27 26 26 addcli ⊢ K + K ∈ ℂ
28 25 27 22 subdiri ⊢ N + D - K + K ⋅ N = N + D ⋅ N − K + K ⋅ N
29 28 oveq1i ⊢ N + D - K + K ⋅ N + M = N + D ⋅ N - K + K ⋅ N + M
30 25 22 mulcli ⊢ N + D ⋅ N ∈ ℂ
31 5 nn0cni ⊢ M ∈ ℂ
32 27 22 mulcli ⊢ K + K ⋅ N ∈ ℂ
33 30 31 32 addsubi ⊢ N + D ⋅ N + M - K + K ⋅ N = N + D ⋅ N - K + K ⋅ N + M
34 10 oveq2i ⊢ N ⋅ N + D ⋅ N + M = N ⋅ N + K ⁢ K
35 22 26 26 adddii ⊢ N ⁢ K + K = N ⁢ K + N ⁢ K
36 34 35 oveq12i ⊢ N ⋅ N + D ⋅ N + M - N ⁢ K + K = N ⋅ N + K ⁢ K - N ⁢ K + N ⁢ K
37 22 24 22 adddiri ⊢ N + D ⋅ N = N ⋅ N + D ⋅ N
38 37 oveq1i ⊢ N + D ⋅ N + M = N ⋅ N + D ⋅ N + M
39 22 22 mulcli ⊢ N ⋅ N ∈ ℂ
40 24 22 mulcli ⊢ D ⋅ N ∈ ℂ
41 39 40 31 addassi ⊢ N ⋅ N + D ⋅ N + M = N ⋅ N + D ⋅ N + M
42 38 41 eqtr2i ⊢ N ⋅ N + D ⋅ N + M = N + D ⋅ N + M
43 22 27 mulcomi ⊢ N ⁢ K + K = K + K ⋅ N
44 42 43 oveq12i ⊢ N ⋅ N + D ⋅ N + M - N ⁢ K + K = N + D ⋅ N + M - K + K ⋅ N
45 36 44 eqtr3i ⊢ N ⋅ N + K ⁢ K - N ⁢ K + N ⁢ K = N + D ⋅ N + M - K + K ⋅ N
46 mulsub ⊢ N ∈ ℂ ∧ K ∈ ℂ ∧ N ∈ ℂ ∧ K ∈ ℂ → N − K ⁢ N − K = N ⋅ N + K ⁢ K - N ⁢ K + N ⁢ K
47 22 26 22 26 46 mp4an ⊢ N − K ⁢ N − K = N ⋅ N + K ⁢ K - N ⁢ K + N ⁢ K
48 6 nn0cni ⊢ L ∈ ℂ
49 22 26 48 subadd2i ⊢ N − K = L ↔ L + K = N
50 9 49 mpbir ⊢ N − K = L
51 50 50 oveq12i ⊢ N − K ⁢ N − K = L ⁢ L
52 47 51 eqtr3i ⊢ N ⋅ N + K ⁢ K - N ⁢ K + N ⁢ K = L ⁢ L
53 45 52 eqtr3i ⊢ N + D ⋅ N + M - K + K ⋅ N = L ⁢ L
54 29 33 53 3eqtr2i ⊢ N + D - K + K ⋅ N + M = L ⁢ L
55 13 1 2 21 6 5 7 8 54 mod2xi ⊢ A E mod N = M mod N