Metamath Proof Explorer


Theorem modeqmodmin

Description: A real number equals the difference of the real number and a positive real number modulo the positive real number. (Contributed by AV, 3-Nov-2018)

Ref Expression
Assertion modeqmodmin ⊢ A ∈ ℝ ∧ M ∈ ℝ + → A mod M = A − M mod M

Proof

Step Hyp Ref Expression
1 modid0 ⊢ M ∈ ℝ + → M mod M = 0
2 1 adantl ⊢ A ∈ ℝ ∧ M ∈ ℝ + → M mod M = 0
3 modge0 ⊢ A ∈ ℝ ∧ M ∈ ℝ + → 0 ≤ A mod M
4 2 3 eqbrtrd ⊢ A ∈ ℝ ∧ M ∈ ℝ + → M mod M ≤ A mod M
5 simpl ⊢ A ∈ ℝ ∧ M ∈ ℝ + → A ∈ ℝ
6 rpre ⊢ M ∈ ℝ + → M ∈ ℝ
7 6 adantl ⊢ A ∈ ℝ ∧ M ∈ ℝ + → M ∈ ℝ
8 simpr ⊢ A ∈ ℝ ∧ M ∈ ℝ + → M ∈ ℝ +
9 modsubdir ⊢ A ∈ ℝ ∧ M ∈ ℝ ∧ M ∈ ℝ + → M mod M ≤ A mod M ↔ A − M mod M = A mod M − M mod M
10 5 7 8 9 syl3anc ⊢ A ∈ ℝ ∧ M ∈ ℝ + → M mod M ≤ A mod M ↔ A − M mod M = A mod M − M mod M
11 4 10 mpbid ⊢ A ∈ ℝ ∧ M ∈ ℝ + → A − M mod M = A mod M − M mod M
12 2 eqcomd ⊢ A ∈ ℝ ∧ M ∈ ℝ + → 0 = M mod M
13 12 oveq2d ⊢ A ∈ ℝ ∧ M ∈ ℝ + → A mod M − 0 = A mod M − M mod M
14 modcl ⊢ A ∈ ℝ ∧ M ∈ ℝ + → A mod M ∈ ℝ
15 14 recnd ⊢ A ∈ ℝ ∧ M ∈ ℝ + → A mod M ∈ ℂ
16 15 subid1d ⊢ A ∈ ℝ ∧ M ∈ ℝ + → A mod M − 0 = A mod M
17 11 13 16 3eqtr2rd ⊢ A ∈ ℝ ∧ M ∈ ℝ + → A mod M = A − M mod M