Metamath Proof Explorer


Theorem motrag

Description: Right angles are preserved by motions. (Contributed by Thierry Arnoux, 16-Dec-2019)

Ref Expression
Hypotheses israg.p ⊢ P = Base G
israg.d ⊢ - ˙ = dist ⁡ G
israg.i ⊢ I = Itv ⁡ G
israg.l ⊢ L = Line 𝒢 ⁡ G
israg.s ⊢ S = pInv 𝒢 ⁡ G
israg.g ⊢ φ → G ∈ 𝒢 Tarski
israg.a ⊢ φ → A ∈ P
israg.b ⊢ φ → B ∈ P
israg.c ⊢ φ → C ∈ P
motrag.f ⊢ φ → F ∈ G Ismt G
motrag.1 ⊢ φ → ⟨“ ABC ”⟩ ∈ ∟ 𝒢 ⁡ G
Assertion motrag ⊢ φ → ⟨“ F ⁡ A F ⁡ B F ⁡ C ”⟩ ∈ ∟ 𝒢 ⁡ G

Proof

Step Hyp Ref Expression
1 israg.p ⊢ P = Base G
2 israg.d ⊢ - ˙ = dist ⁡ G
3 israg.i ⊢ I = Itv ⁡ G
4 israg.l ⊢ L = Line 𝒢 ⁡ G
5 israg.s ⊢ S = pInv 𝒢 ⁡ G
6 israg.g ⊢ φ → G ∈ 𝒢 Tarski
7 israg.a ⊢ φ → A ∈ P
8 israg.b ⊢ φ → B ∈ P
9 israg.c ⊢ φ → C ∈ P
10 motrag.f ⊢ φ → F ∈ G Ismt G
11 motrag.1 ⊢ φ → ⟨“ ABC ”⟩ ∈ ∟ 𝒢 ⁡ G
12 eqid ⊢ ∼ 𝒢 ⁡ G = ∼ 𝒢 ⁡ G
13 1 2 6 10 7 motcl ⊢ φ → F ⁡ A ∈ P
14 1 2 6 10 8 motcl ⊢ φ → F ⁡ B ∈ P
15 1 2 6 10 9 motcl ⊢ φ → F ⁡ C ∈ P
16 eqidd ⊢ φ → F ⁡ A = F ⁡ A
17 eqidd ⊢ φ → F ⁡ B = F ⁡ B
18 eqidd ⊢ φ → F ⁡ C = F ⁡ C
19 1 2 12 6 7 8 9 16 17 18 10 motcgr3 ⊢ φ → ⟨“ ABC ”⟩ ∼ 𝒢 ⁡ G ⟨“ F ⁡ A F ⁡ B F ⁡ C ”⟩
20 1 2 3 4 5 6 7 8 9 12 13 14 15 11 19 ragcgr ⊢ φ → ⟨“ F ⁡ A F ⁡ B F ⁡ C ”⟩ ∈ ∟ 𝒢 ⁡ G