Metamath Proof Explorer


Theorem mpaadgr

Description: Minimal polynomial has degree the degree of the number. (Contributed by Stefan O'Rear, 25-Nov-2014)

Ref Expression
Assertion mpaadgr ⊢ A ∈ 𝔸 → deg ⁡ minPoly 𝔸 ⁡ A = deg 𝔸 ⁡ A

Proof

Step Hyp Ref Expression
1 mpaalem ⊢ A ∈ 𝔸 → minPoly 𝔸 ⁡ A ∈ Poly ⁡ ℚ ∧ deg ⁡ minPoly 𝔸 ⁡ A = deg 𝔸 ⁡ A ∧ minPoly 𝔸 ⁡ A ⁡ A = 0 ∧ coeff ⁡ minPoly 𝔸 ⁡ A ⁡ deg 𝔸 ⁡ A = 1
2 simpr1 ⊢ minPoly 𝔸 ⁡ A ∈ Poly ⁡ ℚ ∧ deg ⁡ minPoly 𝔸 ⁡ A = deg 𝔸 ⁡ A ∧ minPoly 𝔸 ⁡ A ⁡ A = 0 ∧ coeff ⁡ minPoly 𝔸 ⁡ A ⁡ deg 𝔸 ⁡ A = 1 → deg ⁡ minPoly 𝔸 ⁡ A = deg 𝔸 ⁡ A
3 1 2 syl ⊢ A ∈ 𝔸 → deg ⁡ minPoly 𝔸 ⁡ A = deg 𝔸 ⁡ A