Metamath Proof Explorer


Theorem mulcomd

Description: Commutative law for multiplication. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses addcld.1 ⊢ φ → A ∈ ℂ
addcld.2 ⊢ φ → B ∈ ℂ
Assertion mulcomd ⊢ φ → A ⁢ B = B ⁢ A

Proof

Step Hyp Ref Expression
1 addcld.1 ⊢ φ → A ∈ ℂ
2 addcld.2 ⊢ φ → B ∈ ℂ
3 mulcom ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B = B ⁢ A
4 1 2 3 syl2anc ⊢ φ → A ⁢ B = B ⁢ A