Metamath Proof Explorer


Theorem mulneg1d

Description: Product with negative is negative of product. Theorem I.12 of Apostol p. 18. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses mulm1d.1 ⊢ φ → A ∈ ℂ
mulnegd.2 ⊢ φ → B ∈ ℂ
Assertion mulneg1d ⊢ φ → − A ⁢ B = − A ⁢ B

Proof

Step Hyp Ref Expression
1 mulm1d.1 ⊢ φ → A ∈ ℂ
2 mulnegd.2 ⊢ φ → B ∈ ℂ
3 mulneg1 ⊢ A ∈ ℂ ∧ B ∈ ℂ → − A ⁢ B = − A ⁢ B
4 1 2 3 syl2anc ⊢ φ → − A ⁢ B = − A ⁢ B