Metamath Proof Explorer


Theorem negsubd

Description: Relationship between subtraction and negative. Theorem I.3 of Apostol p. 18. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses negidd.1 ⊢ φ → A ∈ ℂ
pncand.2 ⊢ φ → B ∈ ℂ
Assertion negsubd ⊢ φ → A + − B = A − B

Proof

Step Hyp Ref Expression
1 negidd.1 ⊢ φ → A ∈ ℂ
2 pncand.2 ⊢ φ → B ∈ ℂ
3 negsub ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + − B = A − B
4 1 2 3 syl2anc ⊢ φ → A + − B = A − B